1840 United States presidential election in Mississippi
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Elections in Mississippi |
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A presidential election was held in Mississippi from November 3–4, 1840 as part of the 1840 United States presidential election.[1] Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Mississippi voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Mississippi by a margin of 6.86%. As of 2024, this is the only presidential election in American history in which Mississippi has voted for a different candidate than Alabama. This would also be the last time a Democrat (or Democratic splinter) candidate lost Mississippi.
Results
[edit]United States presidential election in Mississippi, 1840[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 19,515 | 53.43% | 4 | 100.00% | ||
Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 17,010 | 46.57% | 0 | 0.00% | ||
Total | 36,525 | 100.00% | 4 | 100.00% |
References
[edit]- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
- ^ "1840 Presidential General Election Results - Mississippi". U.S. Election Atlas. Retrieved December 23, 2013.